AP EAMCET · Maths · Circle
The circle \(S=0\) cuts the circle \(x^2+y^2-4 x+2 y-7=0\) orthogonally. If \((2,3)\) is the centre of the circle \(S=0\), then its radius is
- A 2
- B 1
- C 3
- D 4
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
Given that, \(S=0\) circle cuts the circle \(x^2+y^2-4 x+2 y-7=0\) orthogonally and centre of circle \(S=0\) is \((2,3)\). As we know that, if two circles intersect orthogonally, Then, \(2 g g^{\prime}+2 f f^{\prime}=c+c^{\prime}\) Here, \((g, f)=(2,3)\) and…
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- In List-I, a pair of circles is given in A, B, C and in List-II, angle between those pair of circles is given. Match the items from List-I to List-II.
\begin{array}{lll}
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The correct matching is
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