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AP EAMCET · Maths · Area Under Curves

The area of the region under the curve \(y=|\sin x-\cos x|\), \(0 \leq x \leq \frac{\pi}{2}\) and above \(x\)-axis, is (in square units)

  1. A \(2 \sqrt{2}\)
  2. B \(2 \sqrt{2}-1\)
  3. C \(2(\sqrt{2}-1)\)
  4. D \(2(\sqrt{+1})\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2(\sqrt{2}-1)\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { } y=|\sin x-\cos x|, 0 \leq x \leq \frac{\pi}{2} \\ & \text { Now, Area }=\int_0^{\frac{\pi}{2}}|\sin x-\cos x| d x \\ & =\int_0^{\frac{\pi}{4}}(\cos x-\sin x) d x+\int_{\frac{\pi}{4}}^{\frac{\pi}{2}}(\sin x-\cos x) d x \\ & =[\sin x+\cos…