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AP EAMCET · Maths · Hyperbola

If \(e_1\) and \(e_2\) are respectively the eccentricities of the hyperbola \(\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\) and its conjugate hyperbola, then the line \(\frac{x}{2 e_1}+\frac{y}{2 e_2}=1\) touches the circle having centre at the origin, then its radius is

  1. A 2
  2. B \(e_1+e_2\)
  3. C \(e_1 e_2\)
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(A) 2

Step-by-step Solution

Detailed explanation

Hyperbola : \(\frac{x^2}{a^2}-\frac{y^2}{b^2}=1 ; e_1=\sqrt{\frac{a^2+b^2}{a^2}}\) Conjugate Hyperbola : \(\frac{y^2}{b^2}-\frac{x^2}{a^2}=1 ; e_2=\sqrt{\frac{a^2+b^2}{b^2}}\) Line:…