AP EAMCET · Maths · Permutation Combination
The number of ways that 8 beads of different colours be strung as a necklace is
- A \(2520\)
- B \(2880\)
- C \(4320\)
- D \(5040\)
Answer & Solution
Correct Answer
(A) \(2520\)
Step-by-step Solution
Detailed explanation
Number of ways \[ =\frac{(8-1) !}{2}=\frac{7 !}{2}=2520 \]
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More questions from Maths
- Match for each functions in List - I to its derivative given in List-II
\(\begin{array}{ll}
\hline \text { List I } & \text { List II } \\
\hline \text {(A) } \sin ^{-1}\left(\frac{2 x}{1+x^2}\right) & \text { (I) } \cos x-\sin x \\
\hline \text {(B) } \tan ^{-1}\left(\frac{1-x}{1+x}\right) & \text { (II) } \frac{-1}{1+x^2} \\
\hline \text {(C) } e^{\log (\sin x+\cos x)} & \text { (III) } \frac{2}{1+x^2} \\
\hline \text {(D) } \sqrt{1-\sin 2 x}\left(0 < x < \frac{\pi}{4}\right) & \text { (IV) } \cos x+\sin x \\
\hline & \text { (V) }-\sin x-\cos x \\
\hline
\end{array}\)
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