AP EAMCET · Maths · Straight Lines
The area (in square units) of the triangle formed by the lines \(x=0, y=0\) and \(3 x+4 y=12\) is
- A \(6\)
- B \(\frac{169}{7}\)
- C \(\frac{144}{7}\)
- D \(\frac{72}{7}\)
Answer & Solution
Correct Answer
(A) \(6\)
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