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AP EAMCET · Maths · Quadratic Equation

If the sum of two roots \(\alpha, \beta\) of the equation \(x^4-x^3-8 x^2+\) \(2 x+12=0\) is zero and \(\gamma, \delta(\gamma\gt\delta)\) are its other roots, then \(3 \gamma+2 \delta=\)

  1. A \(0\)
  2. B \(1\)
  3. C \(3\)
  4. D \(5\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(5\)

Step-by-step Solution

Detailed explanation

Given \(\alpha, \beta, \gamma\) and \(\delta\) be the roots of \(x^4-x^3-8 x^2+2 x+12=0\). So, such that \(\alpha+\beta=0\) \(\begin{aligned} & x^4-x^3-8 x^2+2 x+12=\left(x^2+a\right)\left(x^2-x+b\right) \\ & =x^4-x^3+(a+b) x^2-a x+a b\end{aligned}\) After equating co-efficient…