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AP EAMCET · Maths · Vector Algebra

If i^+4j^+3k^,i^+2j^+3k^,3i^+2j^+k^ are position vectors of A,B,C respectively and if D,E are mid points of sides BC and AC, then DE is equal to

  1. A i^+j^+k^
  2. B i^+j^
  3. C j^
  4. D j^+k^
Verified Solution

Answer & Solution

Correct Answer

(C) j^

Step-by-step Solution

Detailed explanation

Given, i^+4j^+3k^,i^+2j^+3k^,3i^+2j^+k^ are position vectors of A,B,C respectively. D is mid point of BC, then position vector of D is 1+3i^+2+2j^+3+1k^2=2i^+2j^+2k^ Similarly, position vector of E is 1+3i^+4+2j^+3+1k^2=2i^+3j^+2k^ Then, DE→=2i^+3j^+2k^-2i^+2j^+2k^=j^.