AP EAMCET · Maths · Parabola
The angle between the tangents drawn to the parabola \(y^2=4 x\) from the point \((1,4)\) is
- A \(\frac{\pi}{4}\)
- B \(\frac{\pi}{3}\)
- C \(\frac{2 \pi}{5}\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{3}\)
Step-by-step Solution
Detailed explanation
Equation of a tangent to a parabola \(y^2=4 x\) is \[ y=m x+\frac{1}{m} \] Since, it passes through point \((1,4)\). So, or \[ 4=m+\frac{1}{m} \]…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If \(\left|\frac{x^2+k x+1}{x^2+x+1}\right| < 3\) for all real numbers \(x\), then the range of the parameter \(k\) isAP EAMCET 2019 Easy
- \(\int \frac{x^8+4}{x^4-2 x^2+2} d x=A x^5+B x^3+C x+k\), then \(5 A+3 B+C=\)AP EAMCET 2022 Medium
- Suppose \(P\) and \(Q\) lie on \(3 x+4 y-4=0\) and \(5 x-y-4=0\) respectively. If the mid-point of \(P Q\) is \((1,5)\), then the slope of the line passing through \(P\) and \(Q\) isAP EAMCET 2022 Easy
- Assertion (A): \(\int_{\frac{\pi}{6}}^{\frac{\pi}{3}} \frac{(\sin x)^{\sqrt{2}} d x}{(\sin x)^{\sqrt{2}}+(\cos x)^{\sqrt{2}}}=\frac{\pi}{12}\)
Reason (R): \(\int_{\frac{\pi}{6}}^{\frac{\pi}{3}} \frac{f(x) d x}{f(x)+f\left(\frac{\pi}{2}-x\right)}=\frac{\pi}{12}\)AP EAMCET 2023 Medium - The circumcentre of the triangle formed by the lines \(x+\) \(y+2=0,2 x+y+8=0\) and \(x-y-2=0\) isAP EAMCET 2024 Medium
- Let \(\bar{a}=2 \bar{i}+3 \bar{j}+\bar{k}, \bar{b}=4 \bar{i}+\bar{j}, \bar{c}=\bar{i}-3 \bar{j}-7 \bar{k}\).
If \(\bar{r}=x \bar{i}+y \bar{j}+z \bar{k}, \bar{r} \cdot \bar{a}=9, \bar{r} \cdot \bar{b}=7, \bar{r} \cdot \bar{c}=6\) then \((x, y, z)=\)AP EAMCET 2022 Easy
More PYQs from AP EAMCET
- The parabola with directrix \(x+2 y-1=0\) and focus \((1,0)\) isAP EAMCET 2020 Easy
- In a compound microscope, the focal lengths of two lenses are \(1.5 \mathrm{~cm}\) and \(6.25 \mathrm{~cm}\). An object is placed at \(2 \mathrm{~cm}\) from the objective and the final image is formed at \(25 \mathrm{~cm}\) from the eye lens. The distance between the two lenses is .............. (in \(\mathrm{cm}\) ).AP EAMCET 2018 Medium
- Which one of the following ions exhibit paramagnetic property?AP EAMCET 2017 Medium
- If the magnitude of the vector product of the vector \(\hat{\mathbf{i}}+\hat{\mathbf{j}}+\hat{\mathbf{k}}\) with a unit vector along the sum of the vectors \(2 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}-5 \hat{\mathbf{k}}\) and \(\lambda \hat{\mathbf{i}}+2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}\) is equal to \(\sqrt{2}\), then the value of ' \(\lambda\) ' isAP EAMCET 2020 Medium
- \(\mathrm{x}+\mathrm{y}+3=0,2 \mathrm{x}-\mathrm{y}+1=0\) are the equations of the asymptotes of a hyperbola. If \((1,-2)\) is a point on this hyperbola, then the equation of its conjugate hyperbola isAP EAMCET 2025 Hard
- A circular disc of radius \(R\) is removed from one end of a bigger circular disc of radius \(2 R\). The centre of mass of the new disc is at a distance \(\alpha R\) from the centre of the bigger disc. The value of \(\alpha\) isAP EAMCET 2018 Medium