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AP EAMCET · Maths · Straight Lines

The circumcentre of the triangle formed by the lines \(x+\) \(y+2=0,2 x+y+8=0\) and \(x-y-2=0\) is

  1. A \((-5,1)\)
  2. B \((-4,0)\)
  3. C \((0,-2)\)
  4. D \(\left(\frac{-8}{3}, \frac{-2}{3}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \((-4,0)\)

Step-by-step Solution

Detailed explanation

\(x+y+2=0\) \(\qquad ....\mathrm{(i)}\) \(\begin{aligned} & 2 x+y+8=0 \qquad ....\mathrm{(ii)}\\ & x-y-2=0 \qquad ....\mathrm{(iii)} \end{aligned}\) Solving (i) and (ii), we get \((x, y)=(-6,4)\) Solving (i) and (iii). we get \((x, y)=(0,-2)\) Solving (ii) and (iii), we get…