AP EAMCET · Maths · Indefinite Integration
Assertion (A): \(\int_{\frac{\pi}{6}}^{\frac{\pi}{3}} \frac{(\sin x)^{\sqrt{2}} d x}{(\sin x)^{\sqrt{2}}+(\cos x)^{\sqrt{2}}}=\frac{\pi}{12}\)
Reason (R): \(\int_{\frac{\pi}{6}}^{\frac{\pi}{3}} \frac{f(x) d x}{f(x)+f\left(\frac{\pi}{2}-x\right)}=\frac{\pi}{12}\)
- A A is true, \(\mathrm{R}\) is true and \(\mathrm{R}\) is the correct explanation of A
- B A is true, \(\mathrm{R}\) is true but \(\mathrm{R}\) is not the correct explanation of \(\mathrm{A}\)
- C \(\mathrm{A}\) is true, \(\mathrm{R}\) is false
- D A is false, \(\mathrm{R}\) is true
Answer & Solution
Correct Answer
(A) A is true, \(\mathrm{R}\) is true and \(\mathrm{R}\) is the correct explanation of A
Step-by-step Solution
Detailed explanation
Let \(\int_{\pi / 6}^{\pi / 3} \frac{(\sin x)^{\sqrt{2}} d x}{(\sin x)^{\sqrt{2}}+(\cos x)^{\sqrt{2}}}...(1)\) Since \(\int_a^b f(x) d x=\int_a^b f(a+b-x) d x\) Hence…
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