AP EAMCET · Maths · Properties of Triangles
In a \(\triangle A B C\), with usual notation, match the items in List-I with the items in List-II and choose the correct option.
- A \(\begin{array}{lllll} \text {A } & \text { B } & \text { C } & \text { D } \\ 4 & 3 & 1 & 5 \end{array}\)
- B \(\begin{array}{lllll} \text {A } & \text { B } & \text { C } & \text { D } \\ 5 & 4 & 3 & 2 \end{array}\)
- C \(\begin{array}{lllll} \text {A } & \text { B } & \text { C } & \text { D } \\ 3 & 1 & 2 & 5 \end{array}\)
- D \(\begin{array}{lllll} \text {A } & \text { B } & \text { C } & \text { D } \\ 4 & 5 & 2 & 1 \end{array}\)
Answer & Solution
Correct Answer
(C) \(\begin{array}{lllll} \text {A } & \text { B } & \text { C } & \text { D } \\ 3 & 1 & 2 & 5 \end{array}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {(A) } r_1 r_2 \sqrt{\frac{4 R-r_1-r_2}{r_1+r_2}}=\left[\frac{\Delta^2}{(s-a)(s-b)}\right. \\ & \left.\sqrt{\frac{4 R-4 R \cos \frac{C}{2}\left(\sin \frac{A}{2} \cos \frac{B}{2}+\sin \frac{B}{2} \cos \frac{A}{2}\right)}{4 R \cos \frac{C}{2}\left(\sin…
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