AP EAMCET · Maths · Vector Algebra
If \(\mathbf{a}\) and \(\mathbf{b}\) are two unit vectors and \(\theta\) is the angle between them, then the unit vector along the angular bisector of \(\mathbf{a}\) and \(\mathbf{b}\) is given by
- A \(\frac{a+b}{2 \sin (\theta / 2)}\)
- B \(\frac{a+b}{2 \cos (\theta / 2)}\)
- C \(\frac{a-b}{(2 \cos \theta / 2)}\)
- D \(\frac{a+b}{\cos (\theta / 2)}\)
Answer & Solution
Correct Answer
(B) \(\frac{a+b}{2 \cos (\theta / 2)}\)
Step-by-step Solution
Detailed explanation
Since \(\mathbf{a}\) and \(\mathbf{b}\) are unit vectors and angle between them is \(\theta\), so unit vector along the angle bisector of \(\mathbf{a}\) and \(\mathbf{b}\) is \(\mathbf{p}=\lambda(\mathbf{a}+\mathbf{b})\) where \(|\mathbf{p}|=\mathbf{l}\). Now, since \(p\) and a…
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