AP EAMCET · Maths · Probability
Two brothers \(X\) and \(Y\) appeared for an exam. Let \(A\) be the event that \(X\) has passed the exam and \(B\) is the event that \(Y\) has passed. The probability of \(A\) is \(\frac{1}{7}\) and of \(B\) is \(\frac{2}{9}\). Then, the probability that both of them pass the exam is
- A \(\frac{1}{63}\)
- B \(\frac{2}{35}\)
- C \(\frac{2}{63}\)
- D \(\frac{9}{14}\)
Answer & Solution
Correct Answer
(C) \(\frac{2}{63}\)
Step-by-step Solution
Detailed explanation
Given, \(A\) be the event that \(x\) is selected and \(B\) is the event that \(y\) is selected. \(P(A)=\frac{1}{7}, P(B)=\frac{2}{9}\) Let \(C\) be the event that both are selected. \(P(C)=P(A) \times P(B)\) as \(A\) and \(B\) are independent events…
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