AP EAMCET · Maths · Parabola
Tangents are drawn at three points \(\mathrm{P}\left(\mathrm{t}_1\right), \mathrm{Q}\left(\mathrm{t}_2\right), \mathrm{R}\left(\mathrm{t}_3\right)\) on the parabola \(\mathrm{y}^2=\mathrm{x}\). Let these tangents intersect each other at the points \(\mathrm{L}, \mathrm{M}, \mathrm{N}\). If \(\mathrm{t}_1=2, \mathrm{t}_2=-4, \mathrm{t}_3=6\), then the area of the triangle LMN is
- A \(24\)
- B \(18.5\)
- C \(7.5\)
- D \(12\)
Answer & Solution
Correct Answer
(C) \(7.5\)
Step-by-step Solution
Detailed explanation
\(y^2=x \Rightarrow 4a=1 \Rightarrow a = 1/4\) \(\mathrm{t}_1-\mathrm{t}_2 = 2-(-4) = 6\) \(\mathrm{t}_2-\mathrm{t}_3 = -4-6 = -10\) \(\mathrm{t}_3-\mathrm{t}_1 = 6-2 = 4\) Area…
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