AP EAMCET · Maths · Permutation Combination
If the letters of the word "ASSASSINATION" are arranged at random in a row, then the probability that no two \(A^{\prime}\) 's come together is equal to
- A \(\frac{25}{26}\)
- B \(\frac{23}{26}\)
- C \(\frac{15}{26}\)
- D \(\frac{17}{26}\)
Answer & Solution
Correct Answer
(C) \(\frac{15}{26}\)
Step-by-step Solution
Detailed explanation
The number of all possible ways to arrange the letters of word ASSASSINATION is \(=\frac{13 !}{3 ! 4 ! 2 ! 2 !}\) Now, the number of ways to arrange the letters \(S, S, S, S, I, N, T, I, O, N\) is \(\frac{10 !}{4 ! 2 ! 2 !}\) and the three \(A^{\prime}\) s we must arrange…
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