AP EAMCET · Maths · Properties of Triangles
For a triangle with the sides of lengths 6,5 and 9, then the radius of the circle is
- A \(\sqrt{3}\)
- B \(\sqrt{2}\)
- C \(\sqrt{5}\)
- D \(\frac{\sqrt{3}}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{2}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \text {In radius } & =\frac{\Delta}{s}=\frac{\sqrt{s(s-a)(s-b)(s-c)}}{s} \\ & =\frac{\sqrt{10(4)(5)(1)}}{10}=\sqrt{2} \end{aligned}\)
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