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AP EAMCET · Maths · Application of Derivatives

The condition that f(x)=ax3+bx2+cx+d has no extreme value, is

  1. A b2>3ac
  2. B b2=4ac
  3. C b2=3ac
  4. D b2<3ac
Verified Solution

Answer & Solution

Correct Answer

(D) b2<3ac

Step-by-step Solution

Detailed explanation

Given curve is f(x)=ax3+bx2+cx+d On differentiating w.r.t. x, we get f'(x)=3ax2+2bx+c For extremum, f'(x)=0⇒3ax2+2bx+c=0 Since, it has no extremum value. ∴Discriminant<0 ⇒(2b)2-4×3a×c<0 ⇒4b2-12ac<0⇒b2-3ac<0 ⇒b2<3ac