AP EAMCET · Maths · Probability
Bag \(B_1\) contains 4 white and 2 black balls. Bag \(B_2\) contains 3 white and 4 black balls. A bag is chosen at random and a ball is drawn from it at random, then the probability that the ball drawn is white, is
- A \(\frac{1}{42}\)
- B \(\frac{42}{32}\)
- C \(\frac{33}{42}\)
- D \(\frac{23}{42}\)
Answer & Solution
Correct Answer
(D) \(\frac{23}{42}\)
Step-by-step Solution
Detailed explanation
Let \(P\left(B_1\right), P\left(B_2\right)\) and \(P(W)\) are the probabilty of selecting bag 1 , bag 2 and white bag respectively. \[ P\left(B_1\right)=\frac{1}{2}=P\left(B_2\right) \]…
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