AP EAMCET · Maths · Determinants
Given that, \(a \alpha^2+2 b \alpha+c \neq 0\) and that the system of equations
\(\begin{aligned} & (a \alpha+b) x+a y+b z=0 \\ & (b \alpha+c) x+b y+c z=0 \\ & (a \alpha+b) y+(b \alpha+c) z=0\end{aligned}\)
has a non-trivial solution, then \(a, b\) and \(c\) lie in
- A Arithmetic progression
- B Geometric progression
- C Harmonic progression
- D Arithmetico-geometric progression
Answer & Solution
Correct Answer
(B) Geometric progression
Step-by-step Solution
Detailed explanation
Given system of equations is \(\begin{aligned}(a \alpha+b) x+a y+b z & =0 \\ (b \alpha+c) x+b y+c z & =0\end{aligned}\) and \((a \alpha+b) y+(b \alpha+c) z=0\) For non-trivial solution,…
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