AP EAMCET · Maths · Probability
If \(A\) and \(B\) are mutually exclusive events with \(P(A)=\frac{1}{4}\) and \(P(B)=\frac{3}{7}\). Then, what is the value of \(P(A / A \cup B)=\) ?
- A \(\frac{7}{19}\)
- B \(\frac{12}{19}\)
- C \(\frac{06}{19}\)
- D \(\frac{13}{19}\)
Answer & Solution
Correct Answer
(A) \(\frac{7}{19}\)
Step-by-step Solution
Detailed explanation
\(A\) and \(B\) are mutually exclusive \[ \begin{aligned} & A \cap B=\phi \Rightarrow P(A \cap B)=0 \\ & \text { and } P(A)=\frac{1}{4} \text { and } P(B)=\frac{3}{7} \end{aligned} \] Now, \(P\left(\frac{A}{A \cup B}\right)=\frac{P(A \cap(A \cup B))}{P(A \cup B)}\)…
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