AP EAMCET · Maths · Trigonometric Equations
Solve \(\tan (x)+\sec (x)=\sqrt{3}, x \in[0,2 \pi]\)
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{6}\)
- C \(\frac{13 \pi}{6}\)
- D \(\frac{6 \pi}{13}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{6}\)
Step-by-step Solution
Detailed explanation
Given trigonometric equation is \(\begin{aligned} & \tan x+\sec x=\sqrt{3}, x \in[0,2 \pi] \\ & \therefore \quad \sec x-\tan x=\frac{1}{\sqrt{3}} \end{aligned}\) So, \(2 \tan x=\sqrt{3}-\frac{1}{\sqrt{3}}\)…
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