AP EAMCET · Maths · Straight Lines
The point to which the origin is to be shifted to remove the first degree terms from the equation \(2 x^2+4 x y-6 y^2+2 x+8 y+1=0\) is
- A \(\left(\frac{7}{8}, \frac{3}{8}\right)\)
- B \(\left(\frac{-7}{8}, \frac{-3}{8}\right)\)
- C \(\left(\frac{-7}{8}, \frac{3}{8}\right)\)
- D \(\left(\frac{7}{8}, \frac{-3}{8}\right)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{-7}{8}, \frac{3}{8}\right)\)
Step-by-step Solution
Detailed explanation
\(2 x^2+4 x y-6 y^2+2 x+8 y+1=0\) is in the form of \[ \begin{aligned} & a x^2+2 h x y+b y^2+2 g x+2 f y+c=0, \text { we get } \\ & a=2, h=2, b=-6, g=1, f=4, c=1 \end{aligned} \] Required point…
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