AP EAMCET · Maths · Pair of Lines
The lines \(3 x^2+8 x y-3 y^2+2 x-4 y-1=0\) and \(4 x-3 y-2=0\)
- A form an equilateral triangle
- B form a right angled triangle
- C form a right angled isosceles triangle
- D are concurrent
Answer & Solution
Correct Answer
(D) are concurrent
Step-by-step Solution
Detailed explanation
\(a=3, h=4, b=-3, g=1, f=-2, c=-1\) \(ab-h^2 = (3)(-3)-(4)^2 = -25\) \(x_p = \frac{hf-bg}{ab-h^2} = \frac{(4)(-2)-(-3)(1)}{-25} = \frac{-5}{-25} = \frac{1}{5}\) \(y_p = \frac{gh-af}{ab-h^2} = \frac{(1)(4)-(3)(-2)}{-25} = \frac{10}{-25} = -\frac{2}{5}\) Intersection point of the…
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