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AP EAMCET · Maths · Permutation Combination

Six persons A, B, C, D, E and F are to be seated at a circular table facing towards the centre. Then the number of ways that can be done if A must have either E or F on his immediate right and E must have either F or D on his immediate right, is

  1. A 18
  2. B 30
  3. C 12
  4. D 24
Verified Solution

Answer & Solution

Correct Answer

(A) 18

Step-by-step Solution

Detailed explanation

There are two cases, I is to the immediate right of A. Number of ways E can fill=3 ways E cannot take sit on the left of A as there will be no space. Number of ways D can fill=1 ways The remaining seats can be filled in 2 ways. The total numbers of ways are 3×1×2=6 The…