AP EAMCET · Maths · Binomial Theorem
The numerically greatest term in the expansion of \((x+3 y)^{13}\), when \(x=\frac{1}{2}\) and \(y=\frac{1}{3}\) is
- A \({ }^{13} \mathrm{C}_9\left(\frac{1}{3}\right)^4\)
- B \({ }^{13} \mathrm{C}_4\left(\frac{1}{2}\right)^9\)
- C \({ }^{13} \mathrm{C}_9\left(\frac{1}{2}\right)^4\)
- D \({ }^{13} C_{10} \frac{1}{2^4}\)
Answer & Solution
Correct Answer
(C) \({ }^{13} \mathrm{C}_9\left(\frac{1}{2}\right)^4\)
Step-by-step Solution
Detailed explanation
Let the \((r+1)^{th}\) term be numerically greatest. For the expansion of \((a+b)^n\), the term is greatest when \( \frac{n-r+1}{r} \left| \frac{b}{a} \right| \ge 1 \). Here, \(n=13\), \(a=x\), \(b=3y\).…
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