AP EAMCET · Maths · Probability
Person \(A\) can solve \(90 \%\) of the problems given in the book and Person \(B\) can solve \(70 \%\). Then, the probability that atleast one of them will solve the proplem selected at random from the book is
- A \(0.16\)
- B \(0.69\)
- C \(0.97\)
- D \(0.20\)
Answer & Solution
Correct Answer
(C) \(0.97\)
Step-by-step Solution
Detailed explanation
Event \(A \Rightarrow A\) solves the problem. Event \(B \Rightarrow B\) solves the problem. \[ \begin{aligned} \mathrm{P}(\text { success }) & =1-P(\bar{A}) \cdot P(\bar{B}) \\ & =1-\frac{10}{100} \times \frac{30}{100} \\ & =1-\frac{3}{100}=\frac{97}{100}=0.97 \end{aligned} \]
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