AP EAMCET · Maths · Straight Lines
If the lines \(4 x+3 y-1=0, x-y+5=0\) and \(k x+5 y-3=0\) are concurrent, then \(k\) is equal to :
- A 4
- B 5
- C 6
- D 7
Answer & Solution
Correct Answer
(C) 6
Step-by-step Solution
Detailed explanation
Since, the given three lines are concurrent, then \(\left|\begin{array}{rrr}4 & 3 & -1 \\ 1 & -1 & 5 \\ k & 5 & -3\end{array}\right|=0\) \(\Rightarrow 4(3-25)-3(-3-5 k)-1(5+k)=0\) \(\Rightarrow-88+9+15 k-5-k=0\) \(\Rightarrow \quad 14 k=84\) \(\therefore \quad k=6\)
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