AP EAMCET · Maths · Parabola
The equation of the tangent to the parabola \(y^2=12 x\) at \((3,-6)\) is
- A \(x-y+9=0\)
- B \(x+y+3=0\)
- C \(x+y-3=0\)
- D \(x=3\)
Answer & Solution
Correct Answer
(B) \(x+y+3=0\)
Step-by-step Solution
Detailed explanation
The equation of tangent to the parabola \(y^2=12 x\) at \((3,-6)\) is \(\begin{array}{llll} y(-6) =6(x+3) \\ \Rightarrow x+y+3 =0 \end{array}\) Hence, option (b) is correct.
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