AP EAMCET · Maths · Probability
Three letters are chosen at random from the letters of the word VARIABLE and all possible three letter words (with or without meaning) are formed with them. Then the probability of getting a three letter word having a consonent as its middle letter is
- A \(\frac{22}{57}\)
- B \(\frac{21}{28}\)
- C \(\frac{43}{57}\)
- D \(\frac{31}{57}\)
Answer & Solution
Correct Answer
(D) \(\frac{31}{57}\)
Step-by-step Solution
Detailed explanation
Total letters in VARIABLE = 8. Distinct letters = {V, A, R, I, B, L, E} (7 distinct). Consonants = {V, R, B, L} (4 distinct). Vowels = {A, I, E} (A is repeated twice). Total ways to form 3-letter words: Case 1: All 3 chosen letters are distinct.…
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