AP EAMCET · Maths · Limits
\(\lim _{n \rightarrow-\infty} \frac{\left[6^2+12^2+18^2+\ldots .+(6 n)^2\right]^2}{[5+10+15+\ldots .+5 n]\left[2^3+4^3+6^3+\ldots .+8 n^3\right]}=\)
- A \(\frac{4}{5}\)
- B \(\frac{144}{5}\)
- C \(\frac{4}{25}\)
- D \(\frac{144}{25}\)
Answer & Solution
Correct Answer
(B) \(\frac{144}{5}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \lim _{n \rightarrow \infty} \frac{\left[6^2+12^2+18^2+\ldots+(6 n)^2\right]^2}{[5+10+15+\ldots+5 n]\left[2^3+4^3+6^3+\ldots+8 n^3\right]} \\ & =\lim _{n \rightarrow \infty}…
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