AP EAMCET · Maths · Trigonometric Ratios & Identities
\(\sqrt{3} \operatorname{cosec} 20^{\circ}-\sec 20^{\circ}\) is equal to
- A \(2\)
- B \(2 \sin 20^{\circ} \cdot \operatorname{cosec} 40^{\circ}\)
- C \(4\)
- D \(4 \sin 20^{\circ} \cdot \operatorname{cosec} 40^{\circ}\)
Answer & Solution
Correct Answer
(C) \(4\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \sqrt{3} \operatorname{cosec} 20^{\circ}-\sec 20^{\circ} \\ &=\frac{\tan 60^{\circ}}{\sin 20^{\circ}}-\frac{1}{\cos 20^{\circ}} \\ &=\frac{\sin 60^{\circ} \cos 20^{\circ}-\sin 20^{\circ} \cos 60^{\circ}}{\cos 60^{\circ} \sin 20^{\circ} \cos 20^{\circ}} \\…
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