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AP EAMCET · Maths · Differential Equations

If \(-\frac{\pi}{4} < x < \frac{\pi}{4}\), then the general solution of the differential equation \(\cos ^2 x \cdot \frac{d y}{d x}-(\tan 2 x) y=\cos ^4 x\) is

  1. A \(y=\frac{1}{2}\left[\frac{\tan 2 x+c}{1-\tan ^2 x}\right]\)
  2. B \(y=\frac{1}{2}\left[\frac{\cos 2 x+c}{1-\tan ^2 x}\right]\)
  3. C \(y=\frac{1}{2}\left[\frac{\sin 2 x+c}{1-\tan ^2 x}\right]\)
  4. D \(y=\frac{1}{2}\left[\frac{\sin x+c}{1-\tan ^2 x}\right]\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(y=\frac{1}{2}\left[\frac{\sin 2 x+c}{1-\tan ^2 x}\right]\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \cos ^2 x \frac{d y}{d x}-\tan 2 x \cdot y=\cos ^4 x \\ & \Rightarrow \frac{d y}{d x}-\frac{\tan 2 x}{\cos ^2 x} y=\cos ^2 x\end{aligned}\) the above differential equation is in the form of. \[ \frac{d y}{d x}+p y=q \text {, } \] where…