AP EAMCET · Maths · Application of Derivatives
\(\mathrm{m}\) is the slope of a tangent to the curve \(\mathrm{e}^{\mathrm{y}}=1+\mathrm{x}^2\) at \(\mathrm{x}=1\) then \(\mathrm{m}=\)
- A \(\frac{2}{\log 2}\)
- B \(\log 2\)
- C 2
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
We are given that the curve is: \[ \begin{aligned} & \mathrm{e}^{\mathrm{y}}=1+\mathrm{x}^2 \\ & \Rightarrow \mathrm{y}=\log _{\mathrm{e}}\left|1+\mathrm{x}^2\right| \end{aligned} \] Now,…
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