AP EAMCET · Maths · Differentiation
If \(y=\frac{\alpha x+\beta}{\gamma x+\delta}\), then \(2 y_1 y_3=\)
- A \(2 y_2^3\)
- B \(3 y_2^2\)
- C \(y_2^2\)
- D \(3 y_3^2\)
Answer & Solution
Correct Answer
(B) \(3 y_2^2\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { } y=\frac{\alpha x+\beta}{\gamma x+\delta} \\ & \Rightarrow y_1=\frac{\alpha(\gamma x+\delta)-\gamma(\alpha x+\beta)}{(\gamma x+\delta)^2}=\frac{\alpha \delta-\gamma \beta}{(\gamma x+\delta)^2}\end{aligned}\)…
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