AP EAMCET · Maths · Vector Algebra
If the adjacent sides of a rectangle are \(\bar{a}=5 \bar{m}-3 \bar{n}, \bar{b}=-\bar{m}-2 \bar{n}\) and the adjacent sides of another rectangle are \(\bar{c}=-4 \bar{m}-\bar{n}, \bar{d}=-\bar{m}+\bar{n}\), then the angle between the vectors \(\bar{x}=\frac{\bar{a}+\bar{c}+\bar{d}}{3}\) and \(\bar{y}=\frac{\bar{c}+\bar{d}}{5}\) is
- A \(\frac{\pi}{2}\)
- B \(\operatorname{Cos}^{-1}\left(\frac{19}{5 \sqrt{43}}\right)\)
- C \(\operatorname{Cos}^{-1}\left(\frac{19}{5 \sqrt{43}}\right)+\pi\)
- D \(\operatorname{Sin}^{-1} \frac{19}{4 \sqrt{43}}\)
Answer & Solution
Correct Answer
(B) \(\operatorname{Cos}^{-1}\left(\frac{19}{5 \sqrt{43}}\right)\)
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Detailed explanation
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