AP EAMCET · Maths · Probability
Seven white balls and three black balls are randomly arranged in a row. The probability that no two black balls are placed adjacently is
- A \(\frac{1}{2}\)
- B \(\frac{7}{15}\)
- C \(\frac{2}{15}\)
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{7}{15}\)
Step-by-step Solution
Detailed explanation
Firstly we fix the seven white balls in alternate position in 7 !. In out of 8 positions 3 black balls can be placed in \({ }^8 P_3\) ways.…
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