ExamBro
ExamBro
AP EAMCET · Maths · Trigonometric Equations

Let \(x, y, z\) be real numbers and \(x \geq y \geq z \geq \frac{\pi}{12}\). If \(x+y+z\) \(=\frac{\pi}{2}\), then the minimum value of \(\cos x \cdot \sin y \cdot \cos z\) is

  1. A \(\frac{1}{2}\)
  2. B \(\frac{1}{4}\)
  3. C \(\frac{1}{6}\)
  4. D \(\frac{1}{8}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{1}{8}\)

Step-by-step Solution

Detailed explanation

Given \(x+y+z=\frac{\pi}{12}\) and \(x \geq y \geq z \geq \quad \frac{\pi}{12}\) Now, Take \(\cos \mathrm{x}\) siny \(\cos \mathrm{z}\).…