AP EAMCET · Maths · Trigonometric Equations
Let \(x, y, z\) be real numbers and \(x \geq y \geq z \geq \frac{\pi}{12}\). If \(x+y+z\) \(=\frac{\pi}{2}\), then the minimum value of \(\cos x \cdot \sin y \cdot \cos z\) is
- A \(\frac{1}{2}\)
- B \(\frac{1}{4}\)
- C \(\frac{1}{6}\)
- D \(\frac{1}{8}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{8}\)
Step-by-step Solution
Detailed explanation
Given \(x+y+z=\frac{\pi}{12}\) and \(x \geq y \geq z \geq \quad \frac{\pi}{12}\) Now, Take \(\cos \mathrm{x}\) siny \(\cos \mathrm{z}\).…
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