AP EAMCET · Maths · Quadratic Equation
Two roots of the equation \(a x^4+b x^3+c x^2+d x+e=0\) are positive and equal. If the product of the other two real roots is 1, then
- A \(\mathrm{be}^2=\mathrm{a}^2 \mathrm{~d}\)
- B \(3 e+\frac{2 b \sqrt{e}}{\sqrt{a}}+c=a\)
- C \(e+2 b \sqrt{e}+3 c=a \sqrt{a}\)
- D \(\mathrm{b}^2 \mathrm{e}=\mathrm{ad}^2\)
Answer & Solution
Correct Answer
(B) \(3 e+\frac{2 b \sqrt{e}}{\sqrt{a}}+c=a\)
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