AP EAMCET · Maths · Circle
Let P be any point on the circle \(x^2+y^2=25\). Let L be the chord of contact of P with respect to the circle \(x^2+y^2=\) 9. The locus of the poles of the lines L with respect to the circle \(x^2+y^2=36\) is
- A \(y^2=20 x\)
- B \(\frac{x^2}{9}+\frac{y^2}{36}=1\)
- C \(x^2+y^2=400\)
- D \(\frac{x^2}{25}-\frac{y^2}{16}=1\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2=400\)
Step-by-step Solution
Detailed explanation
Let \(P(r, s)\) be point on circle \(x^2+y^2=25\) \(\mathrm{r}^2+\mathrm{s}^2=25...(i)\) Equation of chord of contact of \(P\) w.r.t. circle \(x^2+y^2=9\) is L \(\mathrm{L}: \mathrm{xr}+\mathrm{ys}-9=0...(ii)\) Poles of line L w.r.t. circle \(x^2+y^2=36\) is ( \(h, k\) ) then…
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