AP EAMCET · Maths · Properties of Triangles
If \(\Delta=a^2-(b-c)^2\), is the area of the \(\triangle A B C\), then \(\tan A\) is equal to
- A \(\frac{1}{16}\)
- B \(\frac{8}{15}\)
- C \(\frac{3}{4}\)
- D \(\frac{4}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{8}{15}\)
Step-by-step Solution
Detailed explanation
\(\Delta=a^2-(b-c)^2\) \(\Rightarrow \quad \Delta=(a+b-c)(a-b+c)\) \(\Rightarrow \quad \Delta=(2 s-c-c)(2 s-b-b)\) \((\because 2 s=a+b+c)\) \(\Rightarrow \quad \Delta=(2 s-2 c)(2 s-2 b)\) \(\Rightarrow \quad \Delta=4(s-b)(s-c)\) \(\because \Delta=\sqrt{s(s-a)(s-b)(s-c)}\)…
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