AP EAMCET · Chemistry · s Block Elements
Which of the following reactions does no liberate gaseous product ?
- A \(\mathrm{AlCl}_3+\mathrm{NaOH} \longrightarrow\)
- B \(\mathrm{NaOH}+\mathrm{P}\) (white ) \(+\mathrm{H}_2 \mathrm{O} \longrightarrow\)
- C \(\mathrm{Al}+\mathrm{NaOH} \stackrel{\Delta}{\longrightarrow}\)
- D \(\mathrm{Zn}+\mathrm{NaOH} \stackrel{\Delta}{\longrightarrow}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{AlCl}_3+\mathrm{NaOH} \longrightarrow\)
Step-by-step Solution
Detailed explanation
When \(\mathrm{AlCl}_3\) reacts with \(\mathrm{NaOH}\), it forms sodium meta aluminate \(\left(\mathrm{NaAlO}_2\right)\). This reaction does not give gaseous product. \(\mathrm{AlCl}_3+4 \mathrm{NaOH} \longrightarrow \mathrm{NaAlO}_2\) (Sod. meta aluminate (soluble))…
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