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AP EAMCET · PHYSICS · Current Electricity

The length of a potentiometer wires is l. A cell of emf \(E\) is balanced at a length \(\left(\frac{l}{3}\right)\) from positive end of the wire. If the length of the wire is increased by \(\left(\frac{l}{2}\right)\), the distance at which the same cell gives the balancing point is
(Cell in the primary is ideal and no series resistance is present in the primary circuit.)

  1. A \(\frac{2 l}{3}\)
  2. B \(\frac{I}{2}\)
  3. C \(\frac{I}{6}\)
  4. D \(\frac{4 l}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{I}{2}\)

Step-by-step Solution

Detailed explanation

According to question, the figure is as If \(K\) be the potential gradient of the potentiometer wire, then emf of the cell which gives balancing length \(\frac{l}{3}\) is given by \(E=K \cdot \frac{l}{3}\)...(i) Where, \(\quad E=\frac{V}{l} \cdot \frac{l}{3}=\frac{V}{3} \ldots\)…
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