AP EAMCET · Maths · Indefinite Integration
Let \(f(x)=\tan ^{-1}\left(\frac{1+\cos x}{\sin x}\right)\); \(g(x)=\tan ^{-1}\left(\frac{\sin x}{1-\cos x}\right)\), then \(\int(f(x)+g(x)) d x=\)
- A \(\frac{\pi x}{2}-\frac{x^2}{4}\)
- B \(\pi x-\frac{x^2}{2}\)
- C \(\pi x+\frac{x^2}{4}\)
- D \(\pi x+\frac{x^2}{2}\)
Answer & Solution
Correct Answer
(B) \(\pi x-\frac{x^2}{2}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} f(x) & =\tan ^{-1}\left(\frac{1+\cos x}{\sin x}\right) \\ & =\tan ^{-1}\left(\frac{2 \cos ^2 \frac{x}{2}}{2 \sin \frac{x}{2} \cos \frac{x}{2}}\right)=\tan ^{-1}\left(\cot \frac{x}{2}\right) \\ & =\tan ^{-1}\left[\tan…
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