AP EAMCET · Maths · Complex Number
Let \(z=x+i y\) be a complex number with \(x, y \in Z\). Then, the area (in sq units) of the rectangle whose vertices are the roots of the equation \(\bar{z} \cdot z^3+z \cdot \bar{z}^3=350\) is
- A \(48\)
- B \(32\)
- C \(40\)
- D \(44\)
Answer & Solution
Correct Answer
(A) \(48\)
Step-by-step Solution
Detailed explanation
\(\bar{z} z^3+z \bar{z}^3=350\) \(\Rightarrow z \bar{z}\left(z^2+\bar{z}^2\right)=350\) Let \(\quad z=x+i y\) \(\begin{array}{lc}\Rightarrow & \bar{z}=x-i y \\ \therefore & (x+i y)(x-i y)\left[(x+i y)^2+(x-i y)^2\right]=350\end{array}\)…
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