AP EAMCET · Maths · Binomial Theorem
What is the coefficient of \(\frac{y^3}{x^8}\) in \((x+y)^{-5}\), when \(\left|\frac{y}{x}\right| < 1\) ?
- A -35
- B -30
- C -25
- D 10
Answer & Solution
Correct Answer
(A) -35
Step-by-step Solution
Detailed explanation
Since \((x+y)^{-5}=\frac{1}{(x+y)^5}=\frac{1}{x^5}\left(1+\frac{y}{x}\right)^{-5},\left|\frac{y}{x}\right| < 1\) \(\because\) Coefficient of \(\frac{y^3}{x^8} \operatorname{in}(x+y)^{-5}\)…
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