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AP EAMCET · Maths · Functions

Let \(\mathrm{f}: \mathbb{R} \rightarrow \mathbb{R}\) be a function defined by \(\mathrm{f}(\mathrm{x})=\frac{2 \mathrm{x}+1}{3}\). If \(\alpha\) is an element in the domain of \(\mathrm{f}\) whose image is \(\frac{1}{\alpha}\), then the sum of all possible values of such \(\alpha\) is

  1. A \(\frac{-1}{2}\)
  2. B \(\frac{1}{2}\)
  3. C \(\frac{5}{2}\)
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{-1}{2}\)

Step-by-step Solution

Detailed explanation

Given that : \(f(x)=\frac{2 x+1}{3}\) ...(i) Also, \(f(\alpha)=\frac{1}{\alpha}\)…