AP EAMCET · Maths · Functions
Let \(\mathrm{f}: \mathbb{R} \rightarrow \mathbb{R}\) be a function defined by \(\mathrm{f}(\mathrm{x})=\frac{2 \mathrm{x}+1}{3}\). If \(\alpha\) is an element in the domain of \(\mathrm{f}\) whose image is \(\frac{1}{\alpha}\), then the sum of all possible values of such \(\alpha\) is
- A \(\frac{-1}{2}\)
- B \(\frac{1}{2}\)
- C \(\frac{5}{2}\)
- D 0
Answer & Solution
Correct Answer
(A) \(\frac{-1}{2}\)
Step-by-step Solution
Detailed explanation
Given that : \(f(x)=\frac{2 x+1}{3}\) ...(i) Also, \(f(\alpha)=\frac{1}{\alpha}\)…
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