AP EAMCET · Maths · Probability
A person \(P\) speaks truth in \(75 \%\) cases and another person \(R\) in \(80 \%\) cases. Then, the probability that they likely to contradict each other in narrating the same event is
- A \(\frac{7}{20}\)
- B \(\frac{7}{10}\)
- C \(02\)
- D \(0.3\)
Answer & Solution
Correct Answer
(A) \(\frac{7}{20}\)
Step-by-step Solution
Detailed explanation
' Favourable cases - Case I \(A\) speaks truth, \(B\) does not Case II \(B\) speaks truth, \(A\) does not \(\therefore\) Probability \(=\frac{3}{4} \times \frac{1}{5}+\frac{1}{4} \times \frac{4}{5}=\frac{7}{20}\)
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