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AP EAMCET · Maths · Straight Lines

The area (in square units) of the triangle formed by the lines \(6 x^2+13 x y+6 y^2=0\) and \(x+2 y+3=0\) is

  1. A \(\frac{9}{2}\)
  2. B \(\frac{45}{4}\)
  3. C \(\frac{9}{8}\)
  4. D \(\frac{45}{8}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{45}{8}\)

Step-by-step Solution

Detailed explanation

Given the curve, \(6 x^2+13 x y+6 y^2=0\) Comparing with \(a x^2+2 h x y+b y^2=0\), we get \(a=6, b=6, h=\frac{13}{2}\) and a line \(x+2 y+3=0\) comparing with \(l x+m y+n=0\), we get, \(l=1, m=2, n=3\) So, required area…
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