AP EAMCET · Maths · Continuity and Differentiability
Let \(f\) be defined on \(D=[R-\{-1,1\}\) by \(f(x)=\frac{|x|}{1-|x|}\), then
- A f is differentiable on D
- B f is differentiable on D except at x = 0
- C f is continuous but not differentiable on D
- D f is differentiable but not continuous on D
Answer & Solution
Correct Answer
(B) f is differentiable on D except at x = 0
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {We have, } f(x)=\frac{|x|}{1-|x|}=\left\{\begin{array}{l} \frac{-x}{1+x}, x < 0 \\ \frac{x}{1-x}, x \geq 0 \end{array}\right. \\ & \text { LHD }(\text { at } x=0)=\lim _{h \rightarrow 0} \frac{f(0-h)-f(0)}{-h} \\ & =\lim _{h \rightarrow 0}…
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