AP EAMCET · Maths · Definite Integration
\(\int_0^1(\sqrt{10})^{2 x} d x=\)
- A \(\frac{10}{\log 10}\)
- B \(\frac{9}{\log 10}\)
- C \(\frac{1}{\log 10}\)
- D \(\overline{\log 5}\)
Answer & Solution
Correct Answer
(B) \(\frac{9}{\log 10}\)
Step-by-step Solution
Detailed explanation
Let \(I=\int_0^1(\sqrt{10})^{2 x} d x\) \(\begin{aligned} & =\int_0^1 10^{\frac{2 x}{2}} d x=\int_0^1 10^x d x=\left(\frac{10^x}{\log 10}\right)_0^1 \\ & =\frac{10}{\log 10}-\frac{1}{\log 10}=\frac{9}{\log 10} .\end{aligned}\)
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